Also, score matching can be speed using a sliced version as well (https://arxiv.org/abs/1905.07088)

]]>Enfoncons le clou: soit 3 va A,B,C independantes de [0,1] telles que

deux d’entre elles soient uniformes.

Alors $X=A_B, Y=C-B$ sont independantes et uniformes modulo 1

]]>Je concède !

]]>In the Laplace cum Gauss case, t would take roughly the same time, presumably. I was rather thinking of an unsuspected series resolution, when one is unaware of the series being a computable and invertible function…

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