Archive for Montpellier
Loup y es-tu?
Posted in Statistics with tags CIRM, Domaine de l'Hortus, French wines, ISB@CIRM, Languedoc wines, Montpellier, muscat, Pic Saint Loup, sauvignon, summer, Terrasses du Larzac, Viognier, white wines on September 20, 2021 by xi'anHaut-Lirou
Posted in Statistics with tags French wines, Languedoc wines, Languedoc-Roussillon, Montpellier, Pic Saint Loup on April 20, 2021 by xi'angone South [jatp]
Posted in Mountains, pictures, Statistics, Travel, University life, Wines with tags confinement, flight, jatp, Jean-Michel Marin, Méditerranée, Montpellier, Puy de Sancy, snow, Université de Montpellier on March 27, 2021 by xi'andomaine de l’Hortus [blanc]
Posted in Statistics with tags Chardonnay, Dolines de l'Hortus, French wines, Grande Cuvée, Hortus, Languedoc wines, Montpellier, Petit Manseng, Pic Saint Loup, Saint-Martin-de-Londres, Sauvignon Gris, Val de Montferrand, Viognier on July 20, 2020 by xi'anLe Monde puzzle [#1083]
Posted in Books, Kids, R, Travel with tags arithmetics, flight, Le Monde, mathematical puzzle, Montpellier, R, Université de Montpellier on February 7, 2019 by xi'anA Le Monde mathematical puzzle that seems hard to solve without the backup of a computer (and just simple enough to code on a flight to Montpellier):
Given the number N=2,019, find a decomposition of N as a sum of non-trivial powers of integers such that (a) the number of integers in the sum is maximal or (b) all powers are equal to 4. Is it possible to write N as a sum of two powers?
It is straightforward to identify all possible terms in these sums by listing all powers of integers less than N
pool=(1:trunc(sqrt(2019)))^2 for (pow in 3:11) pool=unique(c(pool,(2:trunc(2019^(1/pow)))^pow))
which leads to 57 distinct powers. Sampling at random from this collection at random produces a sum of 21 perfect powers:
1+4+8+9+16+25+27+32+36+49+64+81+100+121+125+128+144+169+196+243+441
But looking at the 22 smallest numbers in the pool of powers leads to 2019, which is a sure answer. Restricting the terms to powers of 4 leads to the sequence
1⁴+2⁴+3⁴+5⁴+6⁴ = 2019
And starting from the pools of all possible powers in a decomposition of 2019 as the sum of two powers shows this is impossible.